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6v^2+33v+15=0
a = 6; b = 33; c = +15;
Δ = b2-4ac
Δ = 332-4·6·15
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-27}{2*6}=\frac{-60}{12} =-5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+27}{2*6}=\frac{-6}{12} =-1/2 $
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